10x^2+9x=16

Solution for 10x^2+9x=16 equation:

10x^2+9x=16

We move all terms to the left:

10x^2+9x-(16)=0

a = 10; b = 9; c = -16;
Δ = b2-4ac
Δ = 92-4·10·(-16)
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{721}}{2*10}=\frac{-9-\sqrt{721}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{721}}{2*10}=\frac{-9+\sqrt{721}}{20}
$